Question

# A block of mass M is pulled along a horizontal rough surface by a rope of mass m by applying a force F at one end of the rope. f is the friction between block and the surface. The force which the rope exerts on the block is:

A
FMm+M+f
B
mFm+Mf
C
mf+FMM+m
D
MFfmMm

Solution

## The correct option is B $$\dfrac{mf+FM}{M+m}$$Friction force is only applied on $$M$$, it is $$f$$.$$(M+m)a=F-f\Rightarrow a=\dfrac{F-f}{M+m}$$So, the force due to rope is: $$Ma+f=\dfrac{mf+FM}{M+m}$$Physics

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