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Question

A block of mass M is pulled along a horizontal rough surface by a rope of mass m by applying a force F at one end of the rope. f is the friction between block and the surface. The force which the rope exerts on the block is:


A
FMm+M+f
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B
mFm+Mf
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C
mf+FMM+m
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D
MFfmMm
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Solution

The correct option is B $$\dfrac{mf+FM}{M+m}$$
Friction force is only applied on $$M$$, it is $$f$$.
$$(M+m)a=F-f\Rightarrow a=\dfrac{F-f}{M+m}$$
So, the force due to rope is: $$Ma+f=\dfrac{mf+FM}{M+m}$$

Physics

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