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Question

A block of mass $$M$$ is pulled by a force F along a smooth horizontal surface with rope of mass $$m$$. The acceleration of the block will be :


A
FM+m
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B
FMm
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C
FM
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D
Fm
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Solution

The correct option is A $$\dfrac {F}{M+m}$$
Let $$a$$ be the acceleration of the block as well as the total system.
mass of total system $$m_t=M+m$$
From FBD, $$F=m_ta=(M+m)a $$
$$\therefore a=\dfrac{F}{M+m}$$
174622_136297_ans_6b44244f28104f8cbe0daef6726d8bd3.png

Physics

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