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Question

A block of mass m moving at a velocity v collides head on with another block of mass 2m at rest. If the coefficient of restitution is 12, find the velocities of the blocks after the collision.


A

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B

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C

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D

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Solution

The correct option is D


Suppose after the collision the block of mass m moves at a velocity u1 and the block of mass 2m moves at a velocity u2. By conservation of momentum,

mv = mu1+2mu2 ..........(i)

the velocity of separation is u2u1 and the velocity of approach is v.

so, u2u1 = 12×(v) ...........(ii)

from (i) and (ii), u1 = 0 and u2 = v2


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