Question

# A block of mass m moving with speed v collides with another block of mass $$2$$m at rest. The lighter block comes to rest after the collision. The coefficient of restitution is?

Solution

## Linear momentum will be conserved: $$mv+2m\times0=2mu+m\times0$$$$\Rightarrow u = \dfrac{v}{2}$$Coefficient of restitution $$e=\dfrac { relative\quad velocity\quad of\quad separation }{ relative\quad velocity\quad of\quad approach\quad }$$$$\\ =\dfrac { v/2 }{ v } =\dfrac { 1 }{ 2 }$$Physics

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