A block of mass m slides along the horizontal track with kinetic friction - - A man pulls the block through a light rope which makes an angle - with the horizontal as shown in the figure - The tension in the light rope is T as shown- The block moves with constant speed V- Power delivered by the man to the block is-

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Byju's Answer

Standard XII

Physics

Gravity

A block of ma...

Question

A block of mass m slides along the horizontal track with kinetic friction $μ$ . A man pulls the block through a light rope which makes an angle $θ$ with the horizontal as shown in the figure . The tension in the light rope is $T$ as shown. The block moves with constant speed $V$ . Power delivered by the man to the block is:

T V

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T V c o s θ

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(T c o s θ - μ m g) V

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Solution

The correct option is B $T V c o s θ$
The man applies only tension T in the given direction of $θ$ with the horizontal.
Thus the power delivered by the man= $\to T . \to V$
$= T V c o s θ$

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The correct option is B TVcosθThe man applies only tension T in the given direction of θ with the horizontal.Thus the power delivered by the man=→T.→V=TVcosθ

The correct option is B $T V c o s θ$
The man applies only tension T in the given direction of $θ$ with the horizontal.
Thus the power delivered by the man= $\to T . \to V$
$= T V c o s θ$