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Question

A block of mass m slides along the horizontal track with kinetic friction $$\mu$$ . A man pulls the block through a light rope which makes an angle $$\theta $$ with the horizontal as shown in the figure . The tension in the light rope is $$T$$ as shown. The block moves with constant speed $$V$$. Power delivered by the man to the block is:

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A
TV
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B
TVcosθ
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C
(Tcosθμmg)V
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D
0
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Solution

The correct option is B $$TV cos \theta$$
The man applies only tension T in the given direction of $$\theta$$ with the horizontal.
Thus the power delivered by the man=$$\vec{T}.\vec{V}$$
$$=TVcos\theta$$

Physics

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