Question

# A block of mass m slides along the horizontal track with kinetic friction $$\mu$$ . A man pulls the block through a light rope which makes an angle $$\theta$$ with the horizontal as shown in the figure . The tension in the light rope is $$T$$ as shown. The block moves with constant speed $$V$$. Power delivered by the man to the block is:

A
TV
B
TVcosθ
C
(Tcosθμmg)V
D
0

Solution

## The correct option is B $$TV cos \theta$$The man applies only tension T in the given direction of $$\theta$$ with the horizontal.Thus the power delivered by the man=$$\vec{T}.\vec{V}$$$$=TVcos\theta$$Physics

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