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Question

A block rests on a rough inclined plane making an angle of 30 with the horizontal. The coefficient of static friction between the block and the plane is 0.8. If the frictional force on the block is 10 N, the mass of the block (in kg) is (take g=10 m/s2)

A
2.5 kg
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B
4 kg
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C
1.6 kg
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D
2 kg
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Solution

The correct option is D 2 kg
The force applied will be component of weight along the incline =mgsinθ=m(10)sin30=5m N

For block to be in rest friction should balance applied force f=mgsin30
f=mgsin30=10 N
m×102=10
m=2 kg

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