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A boat is rowed across the river at the rate of 4.5km/hr. The river flows at the rate of 6km/hr. The velocity of boat in m/s is 

1)2.9

2)3.1

3)2.1

4)5


Solution

  The boat’s velocity and the river velocity will give the boat a new resultant velocity.
As the boat’s velocity is perpendicular to river velocity,
 
Assume that,
                   V= Velocity of boat=4.5 km/hr
                   V= Velocity of river=6 km/hr
 
Apply pythagoras theoram,
 
Resultant velocity boat2 =  VB2 + VR2
resultant velocity boat=square root of 4.5 squared plus 6 squared end root equals 7.5 space k m divided by h r
                                                      = 7.5 cross times 5 over 18 space k m divided by h r
                                                      = 2.083 m/s
                                                      almost equal to 2.1 space m divided by s

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