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Question

A body covers 200cm in the first 2sec and 220cm in next 4sec. Assuming constant acceleration, what is the velocity of the body at the end of 7th second?

A
40cm/sec
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B
20cm/sec
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C
10cm/sec
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D
5cm/sec
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Solution

The correct option is A 10cm/secDistance travelled in first 2 seconds=200cms=ut+12at2200=2u+12a×4u+a=100→(1)Distance travelled in next 4 sec= 220 cmDistance travelled in first 6 sec= 420 cm420=u×6+12a×3670=u+3a→(2)Solving equation 1 and 22a=−30a=−15cm/s2From equation 1 ,u=115cm/sv=u+atv=115+(−15)(7)v=10 cm/s

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