Question

# A body dropped from the top of a tower reaches the ground in $$4\;s$$. Height of the tower is (Take $$g=9.8 \ m/s^2$$):

A
39.2 m
B
44.1 m
C
58.8 m
D
78.4 m

Solution

## The correct option is C $$78.4\ m$$We have, $$s = ut + \frac {1}{2} at^2$$Given, $$t = 4\ sec$$$$a = g$$$$u = 0$$$$\Rightarrow s = \dfrac {1}{2} gt^2$$$$s = \dfrac {1}{2} g(4)^2 = 8g = 8 \times 9.8 = 78.4\ m$$Height of the tower = 78.4 mPhysics

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