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Question

A body falling from rest describes S1,S2 and S3 is the first, second and third seconds of its fall. Then the ratio of S1:S2:S3 is _____________.

A
1:1:1
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B
1:3:5
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C
1:2:3
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D
1:4:9
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Solution

The correct option is B 1:3:5
S=ut+12gt2S=ut+12gt2, u=0u=0
S=12gt2S=12gt2
Here s is displacement.
Distance dropped in 1st1st second, S1=12g×(1)2=12g×1S1=12g×(1)2=12g×1
Distance dropped in 2nd2nd second, S2=12g×(2)212g×(1)2=12g×3S2=12g×(2)2−12g×(1)2=12g×3
Distance dropped in 3rd3rd second, S3=12g×(3)212g×(2)2=12g×5S3=12g×(3)2−12g×(2)2=12g×5
S1:S2:S3=1:3:5

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