Question

A body has an initial velocity of 4 m/s and deceleration of 4 m/s2, then what is its final velocity after traveling 2m?

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Solution

Step1: Given dataInitial velocity, $u=4m/s$Deceleration, $a=-4m/{s}^{2}$Distance, $s=2m$Step2: Formula usedThe third equation of motion says,${v}^{2}={u}^{2}+2as\left[wherev=finalvelocity,u=initialvelocity,a=acceleartion,s=displacement\right]$Step3: Calculating the final velocity${v}^{2}={u}^{2}+2as\phantom{\rule{0ex}{0ex}}{v}^{2}={\left(4\right)}^{2}+2\left(-4\right)\left(2\right)\phantom{\rule{0ex}{0ex}}{v}^{2}=16-16\phantom{\rule{0ex}{0ex}}{v}^{2}=0\phantom{\rule{0ex}{0ex}}v=0$Hence, the final velocity after travelling 2m will be 0.

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