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Question

# A body is dropped from a height 39.2 m. After it crosses the half distance, the acceleration due to gravity ceases to act. Then the body will hit the ground with a velocity of (Take g=9.8 msâˆ’2)

A
19.6 ms1
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B
20 ms1
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C
1.96 ms1
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D
196 ms1
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Solution

## The correct option is A 19.6 ms−1Given that, Height h=39.2 m Initial velocity u=0 Now, from equation of motion After crosses half distance, the acceleration due to gravity ceases to act So, h=39.22 h=19.6m v2−u2=2gh v2=2×9.8×19.6 v=19.6m/s Hence, the velocity is 19.6 m/s

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