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Question

A body is moving with a uniform velocity of 10 m/s on a circular path of diameter 2.0m. calculate

1) the difference between the magnitude of the displacement of the body and the distance covered in half a round and

2) the magnitude of the changes in velocity of the body in half a round.


Solution

Given Diameter =2m

1)After completing a half round the body will reach the diametrical opposite point.
So  as Displacement which is the shortest distance will be the diameter itself.
So displacement=2m.

Now distance covered is equal to half the circumference of the circle as the body completed only half round.
So distance=π×r=π×1=π

Difference in magnitude will be (π-2)m=1.14m


2)As the body is travelling in uniform velocity the magnitude of velocity at each point reamins unchanged even if the direction changes continuously.
So difference in magnitude of velocity after reaching half round will be 0.

Physics

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