A body is projected with a velocity of $98 m s^{- 1}$ . If acceleration due to gravity be $9.8 m / s^{2}$ , then:-

It will go upto the maximum height of

980 m

, after

10 s e c o n d

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It will go upto the height of

490 m

, is

5 s e c o n d

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It will come back to earth in

10 s e c o n d s

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Its speed reduced to

49 m s^{- 1}

after

5 s e c o n d

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Solution

The correct option is D Its speed reduced to $49 m s^{- 1}$ after $5 s e c o n d$
$v = u + a t$
$v = 98 - 9.8 \times 5 = 98 - 49 = 49 m / s$

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A body is projected with a velocity of 98ms−1. If acceleration due to gravity be 9.8m/s2, then:-

The correct option is D Its speed reduced to 49ms−1 after 5secondv=u+atv=98−9.8×5=98−49=49m/s

A body is projected with a velocity of $98 m s^{- 1}$ . If acceleration due to gravity be $9.8 m / s^{2}$ , then:-

The correct option is D Its speed reduced to $49 m s^{- 1}$ after $5 s e c o n d$
$v = u + a t$
$v = 98 - 9.8 \times 5 = 98 - 49 = 49 m / s$