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Question

A body is projected with some initial velocity u at angle π7 with the horizontal. At what angle should another body be thrown so that the horizontal range in both cases is the same?

A
π2
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B
5π14
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C
4π7
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D
6π7
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Solution

The correct option is B 5π14
For a particle projected at an angle θ, range of the particle is given by 2u2sinθcosθg.
If one projects with an angle of π2 θ, the range of the particle will be, 2u2sin(π2θ)cos(π2θ)g
i.e = 2u2cosθsinθg.
For angles = θ and π2 θ, a projectile has the same range.
For angle = π2 π7 = 5π14 the horizontal range will be the same.

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