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Question

A body is released from the top of a tower of height h. It takes t sec to reach the ground. Where will be the ball after time t2 s.                


  1. Depends upon mass and volume of the body

  2. At h/2 from the ground

  3. At 3h/4  from the ground

  4. At h/4 from the ground


Solution

The correct option is C

At 3h/4  from the ground


Let the body after time t2 fall a distance x from the top. Since it starts from rest, we have

x=12gt24=gt28   .............(i)

It reaches the ground in t seconds, we have

h=12gt2 ..............(ii)

Eliminate t from (i) and (ii), we get x = h4

Height of the body from the ground

= hh4=3h4

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