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Question

A body is released from the top of a tower of height h. It takes  t sec to reach the ground. Where will be the ball after time t2 sec
  1. At h/2 from the ground
  2. Depends upon mass and volume of the body
  3. At h/4 from the ground
  4. At 3h/4  from the ground


Solution

The correct option is D At 3h/4  from the ground
Let the body after time t2 be at x from the top, then
x=12g t24=gt28     ...(i)

h=12gt2                   ...(ii) 
Eliminate t from (i) and (ii), we get x=h4 
  Height of the body from the ground =h-h4=3h4  

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