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Question

A body is thrown with a velocity of 20 ms1 from a building of height 15 m. If the angle of projection is 30 above the horizontal, the time of flight and the range of the projectile are respectively.
(Take g=10 m/s2)

A
1 s, 30 m
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B
3 s, 30 m
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C
3 s, 303 m
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D
1 s, 303 m
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Solution

The correct option is C 3 s, 303 m
Displacement of the body in the vertical direction when the body reaches the ground =15 m
(Take downward direction as –ve)
Using second equation of motion, we get
H=usinθ×t12gt2
15=20×12×t5t2
5t210t15=0
t22t3=0
t=3 s (Neglecting negative value)
Range of the projectile =ucosθ×t
=20×32×3
=303 m

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