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Question

A body moves along a circular path of radius $$5m$$. The coefficient of friction between the surface of the path and body is $$0.5$$. The angular velocity, in $$rads^{-1}$$ with which the body should move so that it does not leave the path is ($$g = 10m/s^{2}$$):


A
4
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B
3
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C
2
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D
1
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Solution

The correct option is C $$1$$
Here, Centripetal force $$=$$ Frictional force
$$mr\omega ^2 = \mu mg$$

$$\therefore \omega^2 =\dfrac{ \mu g}{r}$$
$$\therefore \omega^2 =\dfrac{0.5\times 10}{5} = 1$$
$$\therefore \omega = 1\ rad/s$$

Physics

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