A body moves along a straight line with acceleration $3 m s^{- 2}$ for $2$ seconds and then with acceleration $4 m s^{- 2}$ for $3$ seconds. What is his average acceleration?

3.4 m s^{- 2}

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3.5 m s^{- 2}

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3.6 m s^{- 2}

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3.7 m s^{- 2}

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Solution

The correct option is C $3.6 m s^{- 2}$
Given : $a_{1} = 3 m / s^{2}$ $t = 2 s$ and $a_{2} = 4 m / s^{2}$ $t = 3 s$
Average acceleration $a_{a v g} = \frac{a_{1} t_{1} + a_{2} t_{2}}{t_{1} t_{2}}$
$∴$ $a_{a v g} = \frac{3 \times 2 + 4 \times 3}{2 + 3} = 3.6 m / s^{2}$

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A body moves along a straight line with acceleration 3 ms−2 for 2 seconds and then with acceleration 4 ms−2 for 3 seconds. What is his average acceleration?

The correct option is C 3.6 ms−2Given : a1=3m/s2 t=2 s and a2=4m/s2 t=3 sAverage acceleration aavg=a1t1+a2t2t1t2∴ aavg=3×2+4×32+3=3.6 m/s2

A body moves along a straight line with acceleration $3 m s^{- 2}$ for $2$ seconds and then with acceleration $4 m s^{- 2}$ for $3$ seconds. What is his average acceleration?

The correct option is C $3.6 m s^{- 2}$
Given : $a_{1} = 3 m / s^{2}$ $t = 2 s$ and $a_{2} = 4 m / s^{2}$ $t = 3 s$
Average acceleration $a_{a v g} = \frac{a_{1} t_{1} + a_{2} t_{2}}{t_{1} t_{2}}$
$∴$ $a_{a v g} = \frac{3 \times 2 + 4 \times 3}{2 + 3} = 3.6 m / s^{2}$