Question

# A rectangular body of dimensions ( $l×b×h$ ) $2m×3m×4m$ is acted upon by a force of $50N$on the top surface. Calculate the pressure due to the force on that surface.

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Solution

## Step1: Given dataA body of dimensions ( $l×b×h$ ) is $2m×3m×4m$.Force, $f=50N$ Step2: Formula usedThe pressure is defined as the force per unit area which is perpendicular to the surface. The S.I. unit of pressure is Pascal (Pa).$P=\frac{F}{A}\left[whereP=pressure,F=force,A=area\right]$Step3: Calculating pressure$Areaofrec\mathrm{tan}gle=l×b\phantom{\rule{0ex}{0ex}}A=2m×3m\phantom{\rule{0ex}{0ex}}A=6{m}^{2}$Substituting the given value of force and area in the pressure formula$P=\frac{F}{A}\phantom{\rule{0ex}{0ex}}P=\frac{50}{6}\phantom{\rule{0ex}{0ex}}P=8.34Pa$Hence, the pressure due to the force on that surface will be $8.34Pa$.

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