A body of mass 2 kg is thrown up vertically with a KE of 490 J. If the acceleration due to gravity is 9.8ms−2 the height at which the KE of the body becomes half of the original value is:
A
50 m
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B
25 m
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C
12.5 m
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D
10 m
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Solution
The correct option is C 12.5 m By energy conservation, the potential energy at height h= kinetic energy at that height