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Question

A body of mass 200 g oscillates about a horizontal axis at a distance of 20 cm from its center of gravity. If the length of the equivalent simple pendulum is 35 cm, find its moment of inertia about the point of suspension.

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Solution

2πlg=2πImgl
l=Iml
or I=(m)(l)(l)
=(200)(20)(35)
=1.4×105 g-cm2

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