Question

a body of mass $5kg$ is suspended by the strings making angles ${60}^0$ and ${30}^0$ with the horizontal as shown in $Fig.(g=10m{s}^{-2}$. Then

• A. $T_1=25N$
• B. $T_2=25N$
• C. $T_1=25\sqrt{3}N$
• D. $T_2=25\sqrt{3}N$

Answer 1

Answer: (A), (D)

$T_2=25\sqrt{3}N$
$T_1=25N$

Following the FBD,

Equilibrium along X-axis

$T_2$ $cos60-T_1$$cos30=0$

$⟹T_2-\sqrt{3}{T}_1=0--\left(i\right)$

Equilibrium along Y-axis

$T_{2}Sin60-T_{1}Sin30=mg$

$⟹\sqrt{3}{T}_2-T_1=mg=50N--\left(ii\right)$

Solving (i) and (ii), we get

$T_1=25N$

$T_2=25\sqrt{3}N$