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Question

A body of mass 5kg has a momentum of 10kgm/s. When a force of 0.2N is applied on it for 10s, the change in its kinetic energy is:

A
1.1J
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B
2.2J
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C
3.3J
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D
4.4J
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Solution

The correct option is D 4.4J
Given,
Mass, m=5kg
Momentum, p=10kgm/s
Force, F=0,2N
Time, t=10seconds
According to Newton’s second law,
Force = Rate of change of momentum
F=(p2p1)/t
0.2=(mv10)/10
Or mv10=2
Or 5×v10=2
Or v=12/5=2.4m/s
p2 = mv = 5 × 2.4 = 12 kg m/s
Increases in kinetic energy = (p22p12)2m
=(122102)/(2×5)=4.4J


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