You visited us 1 times! Enjoying our articles? Unlock Full Access!

Conservation of Momentum

A body of mas...

Question

A body of mass $m_{1}$ moving with a velocity 10 m/s collides elastically with another body at rest of mass $m_{2}$ . After collision the velocites of the two bodies are 2 m/s and 5 m/s respectively along the direction of motion of $m_{1}$ . The ration of $\frac{m_{1}}{m_{2}} i s$

5/12

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5/8

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

8/5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 5/8
Given,
Initial velocity, of $m_{1}$ and $m_{2}$ is $u_{1}$ and $u_{2}$
Final velocity, of $m_{1}$ and $m_{2}$ is $v_{1}$ and $v_{2}$
From conservation of momentum
Initial momentum = final momentum
$m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}$
$10 m_{1} + m_{2} \times 0 = 2 m_{1} + 5 m_{2}$
$\frac{m_{1}}{m_{2}} = \frac{5}{8}$

Hence, ratio of mass is $\frac{5}{8}$

Suggest Corrections

Similar questions

m_{1}

3 m s^{- 1}

m_{2}

2 m s^{- 1}

5 m s^{- 1}

m_{1}

\frac{m_{1}}{m_{2}}

m_{1}

m_{2}

\begin{matrix} Column - I & Column -II (a) After the collision, velocity of second & (p) > 1 body is maximum when \frac{m_{1}}{m_{2}} is (b) After the collision, the momentum & (q) < 1 of second body is maximum when \frac{m_{1}}{m_{2}} is (c) After the collision, K.E. of second & (r) = 1 body is maximum when \frac{m_{1}}{m_{2}} is (D) For elastic collision, coefficient of & (s) = 0 restitution is \end{matrix}

m_{1}

m_{2}

m_{1}

m_{2}

Join BYJU'S Learning Program