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Question

A body of mass $$m_{1}$$ projected vertically upwards with an initial velocity u reaches a maximum height h. Another body of mass $$m_{2}$$ is projected along an inclined plane making an angle $$30^{{0}}$$ with the horizontal and with speed u. The maximum distance travelled along the incline is


A
2h
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B
h
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C
h2
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D
h4
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Solution

The correct option is C 2h
When thrown vertical, $$v^2-u^2=2gh;v=0$$
On inclined plane, $$v^2-u^2=2gsin\theta h_1=gh_1\ as\ \theta=30^o$$
From above equations, $$h_1=2h$$

Physics

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