A body of mass $m$ accelerates uniformly from rest to $v_{1}$ in time $t_{1}$ . As a function of time $t$ , the instantaneous power delivered to the body is [2004 AIEEE]

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Solution

The correct option is D

$P = \to F . \to v = m a \times a t = m a^{2} t$ [ as u = 0 ]

$= m (\frac{v_{1}}{t_{1}})^{2} t = \frac{m v_{1}^{2} t}{t_{1}^{2}}$ [ As a = $\frac{v_{1}}{t_{1}}$ ]

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accelerates uniformly from rest to velocity

v_{1}

in time interval

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. The instantaneous power delivered to the body as a function of time

t

is:

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A body of mass m accelerates uniformly from rest to v1 in time t1. As a function of time t, the instantaneous power delivered to the body is [2004 AIEEE]

The correct option is D P=→F.→v=ma×at=ma2t [ as u = 0 ] =m(v1t1)2t=mv21tt21 [ As a = v1t1 ]

A body of mass $m$ accelerates uniformly from rest to $v_{1}$ in time $t_{1}$ . As a function of time $t$ , the instantaneous power delivered to the body is [2004 AIEEE]

The correct option is D

$P = \to F . \to v = m a \times a t = m a^{2} t$ [ as u = 0 ]

$= m (\frac{v_{1}}{t_{1}})^{2} t = \frac{m v_{1}^{2} t}{t_{1}^{2}}$ [ As a = $\frac{v_{1}}{t_{1}}$ ]