A body of mass 'm' collides against a wall with a velocity 'v' and retraces its path with the same speed. The change in momentum is (take initial direction of velocity as positive)

Zero

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2Mv

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- 2 Mv

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Solution

The correct option is D
- 2 Mv

Change in momentum = $m {\to v}_{2} - m {\to v}_{1} = - m v - m v = - 2 m v$

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A body of mass 'm' collides against a wall with a velocity 'v' and retraces its path with the same speed. The change in momentum is (take initial direction of velocity as positive)

The correct option is D - 2 Mv Change in momentum = m→v2−m→v1=−mv−mv=−2mv

The correct option is D
- 2 Mv

Change in momentum = $m {\to v}_{2} - m {\to v}_{1} = - m v - m v = - 2 m v$