Question

A body of mass $x$ $kg$ is moving with velocity of $100$ $m$ ${sec}^{-1}$. Its de Broglie wavelength is $6.62\times {10}^{-35}m$. Hence $x$ is:

$[h=6.62\times {10}^{-34}J-sec]$.

• A. $0.25kg$
• B. $0.15kg$
• C. $0.2kg$
• D. $0.1kg$

Answer 1

The correct option is D $0.1kg$

According to de Broglie equation,

$\lambda =\frac{h}{mv}$

$6.62\times {10}^{-35}m=\frac{6.62\times {10}^{-34}J-sec}{xkg\times 100m/s}$

$xkg=\frac{6.62\times {10}^{-34}J-sec}{6.62\times {10}^{-35}m\times 100m/s}$

$x=0.1kg$

Hence, the correct option is $\text{D}$