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Question

A body of volume 100 cm3 weighs 5 kgf in air. It is completely immersed in a liquid of density 1.8 ×103 kg m3. Find : 
(i) the upthrust due to liquid and 
(ii) the weight of the body in liquid. 
(iii) the upthrust on the body. 
State the assumption made in part (i).


Solution

Given: Weight of the body in air, W = 5kgf = 50 N

Volume of the body, V =100 cm3 = 100×106 m3=104 m3

Density of the liquid, d = 1.8 × 10³ kg/m³

(i) The upthrust due to liquid = dVg
=1.8×10³×10⁻⁴×10
=1.8 N

(ii) The weight of the body in liquid = W-B 

= 5 N - 1.8 N
= 3.2 N

(iii) Upthrust on body = Upthrust due to liquid = 1.8 N

The assumption made in part (i) was that the volume of water displaced = volume of the body


Physics
Concise Physics
Standard IX

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