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Question

A body P of mass 1kg undergoes elastic collision with another body Q at rest. After collision, body P continues to move in the original direction with a speed of 14th of its initial speed. Mass of the other body Q is

A
0.06 kg
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B
0.6 gram
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C
600 gram
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D
0.6 kg
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Solution

The correct option is D 0.6 kg
we have formulae,

m1u1+m2u2=m1v1+m2v2
1×u1+0=u14+m2v2

v2=3u14m2

12×1×u21+12×m2×0=12×1×u2116+12×m2×v22
u212=u2132+12m2(3u14m2)2

15u2132=9u2132m2

m2=915

m2=0.6kg

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