Question

A body rotates about a fixed axis with an angular acceleration $1rad/s^2$. The angle (in radians), it rotates during the time in which its angular velocity increases from $5rad/s$ to $15rad/s$ is given by ${10}^x$. Then $x$ is :

Answer 1

${\omega }^2={\omega }_0^2+2\alpha \theta$

$\therefore \theta =\frac{{\omega }^2-{\omega }_0^2}{2\alpha }=\frac{225-25}{2\times 1}$

$=100rad$