Question

# A body rotates about a fixed axis with an angular acceleration $$1 rad/s^{2}$$. The angle (in radians), it rotates during the time in which its angular velocity increases from $$5 rad/s$$ to $$15 rad/s$$ is given by $$10^x$$. Then $$x$$ is :

Solution

## $$\omega ^{2}=\omega _{0}^{2} +2 \alpha \theta$$$$\displaystyle \therefore \theta =\frac{ \omega^{2}-\omega_{0}^{2}}{2\alpha} =\frac{225-25}{2\times 1}$$$$=100\: rad$$Physics

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