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Question

A body starts from rest with uniform acceleration and acquires a velocity V in time T. The instantaneous kinetic energy of the body after any time t is proportional to:


A
(V/T)t
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B
(V2/T)t2
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C
(V2/T2)t
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D
(V2/T2)t2
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Solution

The correct option is D $$(V^{2} / T^{2})t^{2}$$
Here,
$$u=0$$
$$V=0+at$$
Hence, $$a=V/T$$
$$KE=0.5mv^2$$
$$v=at= Vt/T$$
$$KE_t=0.5m(V/T)^2$$
Hence, $$KE \propto \dfrac{V^2 t^2}{T^2}$$

Physics

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