Question

A body thrown up with some initial velocity reaches a maximum height of $50m$. Another body with double the mass thrown up with double the initial velocity will reach a maximum height of :

• A. $100$ m
• B. $200$ m
• C. $400$ m
• D. $50$ m

Answer 1

Answer: (B)

$200$ m

$s\propto u^2$ for maximum height,
$\Rightarrow \frac{s_1}{s_2}=\frac{u_1^2}{u_2^2}$
$\Rightarrow \frac{50}{s_2}=(\frac{u}{2u}{)}^2\Rightarrow s_2=200m$