Question

# A body thrown up with some initial velocity reaches a maximum height of $$50\;m$$. Another body with double the mass thrown up with double the initial velocity will reach a maximum height of :

A
100 m
B
200 m
C
400 m
D
50 m

Solution

## The correct option is C $$200$$ m$$s \propto u^2$$ for maximum height, $$\Rightarrow \dfrac {s_1}{s_2} = \dfrac {u_1^2}{u_2^2}$$$$\Rightarrow \dfrac {50}{s_2} = (\dfrac {u}{2u})^2 \Rightarrow s_2 = 200\ m$$Physics

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