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Question

A body travels a distance of $$3\ km$$ towards East, then $$4\ km$$ towards North and finally $$9\ km$$ towards East.
(i) What is the total distance travelled?
(ii) What is the resultant displacement?


Solution

(i) Total distance travelled $$= 3 + 4 +9=16\ km$$

(ii) The body travels a total distance of $$12\ km$$ in east direction i.e. towards x-axis. 
And it travels a distance of $$4\ km$$ in North direction, i.e. towards y-axis. 

Hence, resultant displacement is 
$$=\sqrt{12^2 + 4^2} = \sqrt{144+ 16} = \sqrt{160} = 12.6km$$

Physics

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