Question

# A body travels a distance of $$3\ km$$ towards East, then $$4\ km$$ towards North and finally $$9\ km$$ towards East. (i) What is the total distance travelled? (ii) What is the resultant displacement?

Solution

## (i) Total distance travelled $$= 3 + 4 +9=16\ km$$(ii) The body travels a total distance of $$12\ km$$ in east direction i.e. towards x-axis. And it travels a distance of $$4\ km$$ in North direction, i.e. towards y-axis. Hence, resultant displacement is $$=\sqrt{12^2 + 4^2} = \sqrt{144+ 16} = \sqrt{160} = 12.6km$$Physics

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