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Question

# A body travels for 15 sec starting from rest with constant acceleration. If it travels distances s1,s2 and s3 in the first five seconds, second five seconds and next five seconds respectively, the relation between s1,s2 and s3 is

A
s1=13s2=15s3
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B
s1=15s2=13s3
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C
2s1=13s2=15s3
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D
s1=16s2=15s3
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Solution

## The correct option is A s1=13s2=15s3Since the body starts from rest. Therefore, u=0 ⇒s1=12a(5)2=25a2 and, s1+s2=12a(10)2=100a2⇒s2=100a2−s1=75a2 Also, s1+s2+s3=12a(15)2=225a2⇒s3=225a2−s2−s1=125a2 ∴ taking the ratio for all three distances, we get s1=13s2=15s3

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