A body when projected up with an initial velocity u goes to a maximum height h in time t and then comes back at the point of projection.The correct statement is:

(a) the average velocity is $\frac{2 h}{t}$

(b) the acceleration is zero

(c) the final velocity on reaching the point of projection is 2u.

(d) the displacement is zero.

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Solution

Given
initial velocity =V m/s
and we know accleration due to gravity =g
time =t sec
height =H meter

average velocity will be

$fraction numerator t o t a l space d i s tan c e over denominator t o t a l space t i m e end fraction equals fraction numerator 2 H over denominator 2 t end fraction left parenthesis a s space t i m e space t o space g o space u p equals t i m e space t o space c o m e space d o w n right parenthesis$

Accerlation = -g

For verification of option 3
Applying equation of motion

hence option 3 is also wrong

so we can say option 4 is correct which is
displacement =0

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Third Equation of Motion

Standard IX Physics

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Given initial velocity =V m/s and we know accleration due to gravity =g time =t sec height =H meter average velocity will be Accerlation = -g For verification of option 3 Applying equation of motion hence option 3 is also wrong so we can say option 4 is correct which is displacement =0