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Question

A boggy of uniformly moving train is suddenly detached from train and stops after covering some distance. The ratio of distance covered by the boggy and distance covered by the train when the boggy has stopped is
  1. 1:1
  2. 3:2
  3. 1:2
  4. 1:4


Solution

The correct option is C 1:2

a= retardation for the boggy

Using v=u+at,
0=uat, taking ve sign for retardation.
t=u/a......(1)

Let St and Sb be the distances coverd by train and boggy respectively.

St=ut=u×ua=u2/a

Using, v2=u22aSb
0=u22aSb
Sb=u22a
Sb=St/2
SbSt=12
 

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