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Question

A bomb is thrown in a horizontal direction with a velocity of 50 m/s. It explodes into two parts of masses 6 Kg and 3 Kg. The heavier fragment continues to move in the horizontal direction with a velocity of 80 m/s. Calculate the velocity of the lighter fragment.

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Solution

Given,

Total Mass, Mtotal=9kg

Initial velocity, Vinitial=50ms1

Lighter Mass =M1

Final velocity of (M2=6kg)part, V2=80ms1
from conservation of momentum

Final momentum = initial momentum

M2V2+M1V1=MtotalVinitial

6×80+3×V1=9×50

V1=10ms1

Final velocity of lighter mass is 10ms1


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