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Question

A bomb of mass 6 kg initially at rest explodes into three identical fragments. One of the fragments moves with a velocity of 103^i m/s, another fragment moves with a velocity of 10^j m/s, then the third fragment moves with a velocity of magnitude:

A
30 m/s
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B
20 m/s
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C
15 m/s
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D
5 m/s
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Solution

The correct option is B 20 m/s
Since the initial momentum is zero, the final momentum should be zero.
Therefore,
mv1+mv2+mv3=0
v3=v1v2
v3=(103^i+10^j)
v3=(103^i+10^j)
v3=(103)2+102
v3=300+100=20 m/s

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