Question

# A bottle of dry Ammonia$\left({\mathrm{NH}}_{3}\right)$and a bottle of dry Hydrogen chloride $\left(\mathrm{HCl}\right)$connected through a long tube are opened simultaneously at both ends. The white ammonium chloride (${\mathrm{NH}}_{4}\mathrm{Cl}$) ring first formed will be:

A

At the center of the tube

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B

Near the hydrogen chloride bottle

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C

Near the ammonia bottle

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D

Throughout the length of the tube

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Solution

## The correct option is B Near the hydrogen chloride bottleExplanation for correct option Option (B) Near the hydrogen chloride bottle ${\mathrm{NH}}_{3}$ is lighter than $\mathrm{HCl}$ thus it diffuses faster. Hence, a white ring of ${\mathrm{NH}}_{4}\mathrm{Cl}$ is formed in the tube near the $\mathrm{HCl}$. Explanation for incorrect option Option a) At the centre of the tube. Since the rate of diffusion of both hydrochloric acid and ammonia is different Hence the ring will not form at the centre .This option is incorrectOption c) Near the Ammonia bottle : we know that the rate of diffusion of ammonia is faster so it will be easily diffused through another end of the tube Hence the ring will not form near the ammonia bottle.Option is incorrectOption d) Throughout the length of the tube.This option is incorrect since ammonia is diffusing at a faster rate Thus it will reach the other bottle soon and react to give the product.Hence The white ammonium chloride ${\mathrm{NH}}_{4}\mathrm{Cl}$ ring will be first formed Near the Hydrogen chloride bottle.

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