CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A box contains 12 balls of which some are red in colour . If 6 more red balls are put in the box and a ball is drawn at random , the probability of drawing a red ball doubles than what it was before . Find the number of red balls in the box .

Open in App
Solution

Let the total number of red balls initially be x

Total number of balls in the box = 12

P(getting a red ball) = x/12

Now, 6 red balls are put in the box, then the total number of balls

= 12 + 6

= 18 balls

Then total number of red balls = (x + 6)

Now,

P(getting a red ball) = (x + 6)/18

According to the question.

2(x/12) = (x + 6)/18

2x/12 = (x + 6)/18

Cross multiplying

⇒ 36x = 12x + 72

⇒ 36x - 12x = 72

⇒ 24x = 72

x = 3

So, initially the number of red balls in the box were 3.

Hope it helps
All the best.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Theoretical Probability
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon