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Question

A box contains 12 balls out of which x are blue. If one ball is drawn at random from the box, what is the probability that it will be a blue ball ? If 6 more blue balls are put in the box , the probability of drawing a blue ball is now double of what it was before . Find x


A

(i) x12 (ii) 3

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B

(i) x6 (ii) 4

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C

(i) x6 (ii) 5

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D

(i) x4 (ii) 2

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Solution

The correct option is A

(i) x12 (ii) 3


Number of blue balls = x

Total number of balls = 12

Hence P ( getting a blue ball ) = x12

(ii) Value of x

6 more blue balls were added . Hence P( getting blue ball ) = x+612+6

= x+618

Given that the probablity of drawing a blue ball is now doubled

Hence x+618 = 2 × x12

x+618 = 2 × x6

6x + 36 = 18 x

12 x = 36

x = 3


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