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Question

A box contains 3 white and 2 red balls. If the first drawn ball was not replaced then the probability that the second drawing ball will be red is

A
825
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B
25
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C
35
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D
2135
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Solution

The correct option is B 25
Let A the event that drawn ball is white.
B the event that drawn ball is red.
There are two mutually exclusive cases of the required event: WR and RR
Now P(WR)=P(W)P(RW)=35.24=620
P(RR)=P(R)P(RR)=25.14=220
Required Probability=P(WR+RR)=P(WR)+P(RR)
=620+220=820=25

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