Question

A box contains $5$ red marbles, $8$ white marbles and $4$ green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be (i) red ? (ii) white ? (iii) not green?

Answer 1

Total number of marbles in the box $=5+8+4=17$

i) P(red) = no. of red marbles/total number of marbles

P(red) $=\frac{5}{17}$

ii) P(white) = no. of white marbles/total number of marbles

P(white) $=\frac{8}{17}$

iii) P(green) = no. of green marbles/total number of marbles

P(green) $=\frac{4}{17}$

P(not green) $=1-$ P(green) $=\frac{13}{17}$