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Question

A box contains 6 tickets. Two of the tickets carry a prize of Rs. 5/- each, the other four a prize of Rs.1/-. If one ticket is drawn. The mean value of prize is


A
Rs. 2.5
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B
Rs. 7/3
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C
Rs. 5/3
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D
Rs.4/3
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Solution

The correct option is B Rs. $$7/3$$
The probability of drawing a ticket out of six is $$\dfrac{1}{6}$$
Hence the mean prize if one ticket is drawn is
$$(5(\dfrac{1}{6}))+(5(\dfrac{1}{6}))+(\dfrac{1}{6})+((\dfrac{1}{6}))+(\dfrac{1}{6}))+((\dfrac{1}{6}))$$
$$=2\times[5\times\dfrac{1}{6}]+\dfrac{4}{6}$$
$$=\dfrac{10}{6}+\dfrac{4}{6}$$
$$=\dfrac{14}{6}$$
$$=\dfrac{7}{3}$$ rupees.

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