Question

A box of mass $3kg$ is attached to a vertical spring of spring constant $50N/m$. How far is the equilibrium position of this spring system from the point where the spring exerts no force on the box?

• A. $0.15m$
• B. $0.3m$
• C. $0.5m$
• D. $0.6m$
• E. $1.5m$

Answer 1

The correct option is D $0.6m$

Given : $m=3kg$ $k=50$ $N/m$ $g=10m/s^2$

O represents the point where the spring does not exert force on the box.

Let the distance between the box and the point O be $x$.

At equilibrium, $kx=mg$

$⟹x=\frac{mg}{k}=\frac{3\times 10}{50}=0.6$ $m$