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Question

A boy carrying a bag on his shoulders walking at angle of 90 degrees does any work or not


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Solution

Work done by force

  1. Work done is the total amount of necessary energy to bring a body from one point to another point. Work done is the dot product of force and displacement.
  2. The work done by a body is defined by the form, w=F×ds×cosθ, where F is the force exerted on the body and s is the displacement of the body due to the force.

Explanation

  1. The boy carrying a bag on his shoulders walking horizontally. So, the displacement of the boy and the bag is horizontal.
  2. But, due to the bag, a weight (gravitational force) is acting downwards (vertically). So, the displacement and applied force of the boy are perpendicular to each other, i.e, the angle between displacement and force is 90o. So, the work done is zero.

Calculation

Now, from the formulae of work done,

w=F×ds×cosθ=0orw=0.,

As we know cos90=0.

Therefore, the boy carrying a bag on his shoulders walking at an angle of 90 degrees, in this case, the work done is zero.


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