A boy is throwing balls into the air one by one in such a way that when the first ball thrown reaches maximum height he starts to throw the second ball. He repeats this activity. To what height do the balls rise if he throws twice in a second?

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Solution

Time to reach maximum height $= \frac{u}{g}$
$\frac{u}{g} = 1 s$
$u = g m / s$
$H_{m a x} = \frac{u^{2}}{2 g} = \frac{g^{2}}{2 g} = \frac{g}{2} = 5 m$

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A boy is throwing balls into the air one by one in such a way that when the first ball thrown reaches maximum height he starts to throw the second ball. He repeats this activity. To what height do the balls rise if he throws twice in a second?

Time to reach maximum height =ugug=1su=gm/sHmax=u22g=g22g=g2=5m

Time to reach maximum height $= \frac{u}{g}$
$\frac{u}{g} = 1 s$
$u = g m / s$
$H_{m a x} = \frac{u^{2}}{2 g} = \frac{g^{2}}{2 g} = \frac{g}{2} = 5 m$